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HDU 4618 Palindrome Sub-Array
阅读量:6083 次
发布时间:2019-06-20

本文共 1718 字,大约阅读时间需要 5 分钟。

Palindrome Sub-Array

Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 65535/32768 K (Java/Others)

Total Submission(s): 751    Accepted Submission(s): 366

Problem Description
  A palindrome sequence is a sequence which is as same as its reversed order. For example, 1 2 3 2 1 is a palindrome sequence, but 1 2 3 2 2 is not. Given a 2-D array of N rows and M columns, your task is to find a maximum sub-array of P rows and P columns, of which each row and each column is a palindrome sequence.
 

 

Input
  The first line of input contains only one integer, T, the number of test cases. Following T blocks, each block describe one test case.
  There is two integers N, M (1<=N, M<=300) separated by one white space in the first line of each block, representing the size of the 2-D array.
  Then N lines follow, each line contains M integers separated by white spaces, representing the elements of the 2-D array. All the elements in the 2-D array will be larger than 0 and no more than 31415926.
 

 

Output
  For each test case, output P only, the size of the maximum sub-array that you need to find.
 

 

Sample Input
1 5 10 1 2 3 3 2 4 5 6 7 8 1 2 3 3 2 4 5 6 7 8 1 2 3 3 2 4 5 6 7 8 1 2 3 3 2 4 5 6 7 8 1 2 3 9 10 4 5 6 7 8
 

 

Sample Output
4
 

 

Source
 

 

Recommend
zhuyuanchen520
 

刚开始想多了,今天看看,暴力模拟就可以了

#include
#include
#include
#include
#include
using namespace std;int n,m,num[320][320];int ok(int x){ int flag; for(int i=1;i<=n-x+1;i++){ for(int j=1;j<=m-x+1;j++){ flag=1; for(int l=i;l<=x+i-1 && flag;l++) for(int r=j;r
1;i--) if(ok(i)){ printf("%d\n",i); break; } if(i==1) printf("1\n"); } return 0;}

 

 

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